integrate with respect to x the function f(x)= xln(x)
Use integration by parts
let u=ln(x)
let dv/dx=x
therefore du/dx=1/x and v=(1/2)x^2
therefore the integral of xln(x) is equal to the following:
(1/2)x^2ln(x) - (integral with respect to x of:((1/2)x^2)/x)
= (1/2)x^2ln(x) - (integral with respect to x of:((1/2)x))
=(1/4)x^2(2ln(x)-1) + c
(I will explain further how I reached this answer during the session with provision of the whiteboard to evaluate my integrals)
PJ
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