solve 2cos^2(x) - cos(x) = 0 on the interval 0<=x < 180
we start y factoring and solving for each equation:
cos(x) (2cos(x) - 1) = 0
this means:
cos(x) = 0 and cos(x) = 1/2
from the first equation we get: x = 90
and from the second equation using the known trigonometric triangles we get
x = 60
therefore x = 60, 90 in the interval asked.
DS
Related Maths A Level answers
All answers ▸Use the geometric series formula to find the 9th term in this progression : 12 18 27...
Two particles A and B of mass 2kg and 3kg respectively are moving head on. A is moving at 5m/s and B is moving at 4m/s. After the collision, A rebounds at 4m/s. What is the speed of B and what direction is it moving in?
Integrate 2sin^3(x)+3.
Express the following in partial fractions: (x^2+4x+10)/(x+3)(x+4)(x+5)