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Integrate 2x/[(x+1)(2x-4)

2x/[(x+1)(2x-4)] = [A/(x+1) + B/(2x-4)]x = A(x-2) + B(x+1)x = -1-1 = A(-3)A = 1/3x = 2 2 = B(3)B = 2/3 therefore.... 2x/[(x+1)(2x-4)] = [(1/3)/(x+1) + (2/3)/(x-2)]Using the identification method of integration....Integral of 2x/[(x+1)(2x-4)] = (1/3)ln(x+1) + (2/3)ln(x-2)

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Integrate 2x/[(x+1)(2x-4)

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