Solve 11 – 4y = 6y – 3

In order to solve the question, we must find the value of y. First, we collect 'like terms'. This is when we put all the numbers on one side of the equals sign and put all the terms with y in it on the other. So for this equation, I will move -4y to the other side of the equals sign where it changes from -4y to +4y, the sign always changes whenever we move something across the equals sign. Then I will move the -3 to the other side where it will become +3. The equation will therefore look like this:11+3=6y+4y Then we will simplify both sides: 11+3=14 and 6y+4y=10y. The equation would then be: 14=10y. To solve for y we must divide both sides by 10 - this will cancel the 10 from 10 y leaving: 1.4=y so the answer is 1.4.

GE

Related Maths GCSE answers

All answers ▸

The two points (4,9) and (2,3) are on line A. A second line, line B is perpendicular to line A and goes through the point (2,3). What is the equation of line B?


Solve the simultaneous equations 5x+2y=11 and x-y=-2.


Make y the subject of the formula: p = √x+y/5


A particle P of mass 0.4 kg is moving under the action of a constant force F newtons. Initially the velocity of P is (6i – 27j) m s−1 and 4 s later the velocity of P is (−14i + 21j) m s−1 . Find, in terms of i and j, the acceleration of P.