If x is a real number, what are the solutions to the quadratic: 4*x^2- 4*x+1 = 0
You first calculate the delta of the equation: delta = b^2-4ac = 16 - 16 = 0 => the solution is double.x1,2 = (-b±sqrt(delta))/2/a = 4/2/4 = 1/2 which is real.so the solutions are 1/2 and 1/2.
MI
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