If x is a real number, what are the solutions to the quadratic: 4*x^2- 4*x+1 = 0

You first calculate the delta of the equation: delta = b^2-4ac = 16 - 16 = 0 => the solution is double.x1,2 = (-b±sqrt(delta))/2/a = 4/2/4 = 1/2 which is real.so the solutions are 1/2 and 1/2.

MI
Answered by Maria I. Maths tutor

2946 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the integral of (3x^2+4x^5-7)dx


y = 3x^2 + 2x^(1/2) - 12 Find dy/dx


What is the integral of sin(3x) cos(5x)?


Can you differentiate y = (x^4 + x)^10


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences