Solve algebraically the simultaneous equations 3x + 2y = 15 and 2x + 4y = 10

Firstly, we need to eliminate on of the terms of the equation, either the x or the y term, by combining the two equations into one equation. To do this we can add or subtract the two equations from each other to make one term disappear: For example if we times the first equation by 2 it becomes 6x + 4y = 30. We can then subtract the second equation from this new equation: 6x + 4y = 30 minus 2x + 4y = 10. This equals 4x = 20. Solve to find x, x = 20/4 = 5.We can now use this x value to find what y equals by substituting the x value into one of the equations.For example 3(5) + 2y = 15 which simplifies to 15 + 2y = 15 so y = 0.

EB
Answered by Eleanor B. Maths tutor

4522 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

There are 20 sweets in a bag, 5 are white and 15 are black. What is the probability that a sweet chosen at random will be white?


Find the point(s) of intersection of the curve y=x^2+7x+14 and y=2x+8:


Do you have any tips for revising for my GCSE Maths Exam?


How do you solve an algebraic equation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning