Find the integral of y=6/(e^x+2) using calculus.
First, use the substitution u=e^x (which implies dx=du/u) to make the integral ∫6/(u*(u+2)))du. Next seperate the fraction using partial fractions and expand to form 3∫1/u du - 3∫1/(u+2) du. Next integrate to get 3lnu - 3ln(u+2) + C. Finally, don't forget the "+ C"!
JP
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