Solve this set of simultaneous equations. 1. 4x+2y=12 2. 2x+3y=10

To solve simultaneous equations we need to make either the y coefficients or the x coefficients equal so that we can cancel them out. For this set of equations we are going to make the x coefficients the same. To make them the same we need to find a common factor. In this example the common factor of 4 and 2 is 4. We need to multiply our equations to make 4 the coefficient of x for both. Therefore, we need to multiply equation 1 by 1 and equation 2 by 2. This gives us the equations 1. 4x+2y=12 and 2. 4x+6y=20. In order to cancel out the x's we need to subtract equation 1 from equation 2. This gives 4y=8. We are now able to work out the value of y as only have one unknown. To find y we divide both sides by 4 so y=2.
Now that we know the value of y we can substitute it into one of the original equations to find the value of x. We know y=2 so if we substitute this into equation 1 this gives us 4x+4=12. We now only have one unknown in this equation so can rearrange it to find x. Subtract 4 from both sides to get 4x=8. Finally divide both sides by 4 to give x=2. The final answer is y=2, x=2.

GB
Answered by Georgia B. Maths tutor

3626 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find the value of x which satisfies the following equation 3x^2 +6x+3 = 0


Solve the simultaneous equations 4x + 2y =20 and 8x + 6y =45


Line L1 passes through points (4,6) and (12,2). Line L2 passes through the origin and has gradient -3. The two lines intersect at point P. Find the co-ordinates of P.


Simplify 7h + 5k + h - 7k


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences