How do you solve between the two simultaneous equations 2x+y=4 and 3x+2y =6?

First label your two simultaneous equations1)2x+y=42)3x+2y=6Then rearrange 1)1*) y=4-2xNow sub 1*) into 2)3x + 2(4-2x)=6and expand brackets and solve for x3x+8-4x=6-x=-2x=2Now sub x=2 into 1)2(2)+y=4y=0

SK

Related Maths GCSE answers

All answers ▸

Solve (72x^3 - 18x)/(12x^2 - 6x) = 0 for x.


Simplify fully 3(3 – x) – 2(x – 4)


Solve the equation for x: 3x^2 -5 = 22


The point P, (-1,4) lies on a circle C that is centered about the origin. Find the equation of the tangent to the circle at point P.