Integrate 3x^4-4x^2+3/x

Firstly, integrate each term individually, starting off with the 3x^4. In order to integrate the index on the x term needs to be raised by 1, and the coefficient of the x should be divided by this new value. In this case; 4+1=5, which is the new index. 3/5 is the new coefficient. Therefore this term equals to 3/5x^5. Doing the same with the next 2 terms and integrating 3/x to 3ln(x) using the integral rule, you will end with the result of 3/5x^5-4/3x^3+3ln(x)+C. Ensure that the "+C" is always included as it contributes towards the marks.

Answered by Muhammad R. Maths tutor

2309 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the turning points and their nature of the graph y = x^3/3 - 7x^2/2 + 12x + 4


I don't understand the point of differentiation or integration


Differentiate the equation y = x^2 + 3x + 1 with respect to x.


The line AB has equation 5x + 3y + 3 = 0. The line AB is parallel to the line y = mx + 7. Find the value of m.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy