How would you use the Integration Factor method to solve an ordinary first-order linear differential equation?

The word "ordinary" means that there are only two variables, "first-order" means that the highest derivative is the first derivative and "linear" means that the highest power of the function variable is 1. Therefore, the Integration Factor method is applicable.First, you get values with the function variable (y for dy/dx) on the left and the parameter variable (x for dy/dx) on the right. You integrate the coefficient of y with respect to x to get the "Integration Factor (IF)". Then, multiply both sides of the differential equation by IF. Here, you get y multiplied by IF equal to the integral of the right hand side of the new differential equation. Solve the integral and divide by IF to get y(x).

Related Further Mathematics A Level answers

All answers ▸

Solve for z in the equation sin(z) = 2


Prove by induction that for all positive integers n , f(n) = 2^(3n+1) + 3*5^(2n+1) , is divisible by 17.


Unfortunately this box is to small to contain the question so please see the first paragraph of the answer box for the question.


When using the method of partial fractions how do you choose what type of numerator to use and how do you know how many partial fractions there are?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy