Find the turning points of the curve y=2x^3 - 3x^2 - 14.
First differentiate the equation: dy/dx = 6x^2 - 6xSet this equal to 0 as at turning points the change in gradient is 0: 0 = 6x^2 - 6x6x(x-1)=06x=0 therefore x=0(x-1)=0 therefore x=1x=1,0Now substitute back into equation 1 to find y values and hence co ordinatesx=1 y=-15x=0 y=-14
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