How do I differentiate an expression of the form y = (ax+b)^n?

In order to differentiate this we need to use the chain rule- first let u = ax + b. Then differentiating, du/dx = a. By substituting into the original expression, we can obtain y = u^n. Differentiating that gives dy/du = nu^(n-1). Since, using the chain rule, dy/dx = du/dx * dy/du = anu^(n-1). Subbing back in for u, we obtain our answer: an(ax+b)^(n-1).

SC
Answered by Sam C. Maths tutor

10295 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

find the integral of ((3x-2)/(6x^2-8x+3)) with respect to x between x=2 and x=1. (hint use substitution u=denominator)


A particle is in equilibrium under the action of four horizontal forces of magnitudes 5 newtons acting vertically upwards ,8 newtons acting 30 degrees from the horizontal towards the left,P newtons acting vertically downwards and Q newtons acting to right


How do I solve quadratic equation by completing the square : X^2 - 4X = 5


How do I find the co-ordinates of a stationary point of a given line and determine whether it is a minimum or a maximum point?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences