Solve the simultaneous equation by elimination: 3x + y = 11 and 5x + y = 4

Simultaneous equations have at least two unknowns that must have the same value in each equation. This means the value of x and y in both equations must be the same. To solve this by elimination, the aim is to first remove one of the unknowns and then calculate the other. In this case, variable y has the same coefficient of 1 in both equations so it can be "eliminated" by subtracting the two equations. The trick is to subtract each term: 3x - 5x = -2x; y - y = 0; 11- 4 = 7 Hence, we're left with: -2x = 7. By dividing both sides of the equation by -2, we can see that x = -3.5. Now we can find the value for y using any of the equations. Using the first equation, if we plug in x = -3.5, we have -10.5 + y = 11; by adding 10.5 to both sides of the equation, we get y = 21.5. To cross-check the answer, plug in the value of x (-3.5) and y (21.5) to both equations to ensure you get 11 and 4 respectively. If you don't, you've made a mistake somewhere along the line. x = -3.5 and y = 21.5 are the unique solutions to these equations.

MA
Answered by Moyin A. Maths tutor

4266 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

161/5 x 26x =


x = 0.045 (45 recurring). Prove algebraically that x can be written as 1/22


Sarah asked 20 people at a tennis tournament how they travelled there. She found that 13 of them travelled by car. Estimate how many of the total 2000 people at the tournament travelled by car.


What's the best way to work out any percentage of a given number, e.g. 63% of 450?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning