How to differentiate y=x^3+4x+1 when x=3

First of all you calculate dy/dx. To do this you look at each x individually. For the first x you multiply it by it's power and then minus 1 from the power to get 3x^2. Then multiply the next x by the power and minus 1 to get 4x. As 1 is the same as 1 multiplied by x^0, this means that you multiply 1 by 0 to get 0. Therefore dy/dx is 3x^2 + 4. Now substitute in x=3 to get dy/dx=31. This is the gradient.

LS
Answered by Leana S. Maths tutor

2792 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Question 3 on the OCR MEI C3 June 2015 paper. Find the exact value of Integral x^3 ln x dx between 1 and 2.


(4-2x)/(2x+1)(x+1)(x+3) = A/(2x+1)+B/(x+1)+C(x+3) Find the values of the constants A, B and C


f(x) = (4x + 1)/(x - 2). Find f'(x)


Using a suitable substitution, or otherwise, find the integral of [x/((7+2*(x^2))^2)].


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences