Find the values of x given the equation (4x^2)-3x+1=2 using the quadratic formula.

4x2-3x+1=2The first step is to rearrange the equation, equating it to zero: 4x2-3x+1-2=0 which gives 4x2-3x-1=0. Next we apply the quadratic formula: x=(-b +/- sqrt(b2-4ac))/2a where a=4, b=-3 and c=-1. Substituting the values into the formula gives: x=(-(-3) +/- sqrt((-3)2-4(-4)))/2a. Simplifying gives: x=(3 +/- sqrt(25))/8. Solving this gives x=1 and x=-0.25.

SM
Answered by Shahnaan M. Maths tutor

3275 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Rationalise the denominator of 6/√3 and simplify your answer.


Solve the folllowing quadratic equation: y=x^2+x-6


Simply fully (3x^2 - 8x - 3) / 2x^2 - 6x


expand out the bracket (2m - 3)(m + 1).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences