Find the values of x given the equation (4x^2)-3x+1=2 using the quadratic formula.
4x2-3x+1=2The first step is to rearrange the equation, equating it to zero: 4x2-3x+1-2=0 which gives 4x2-3x-1=0. Next we apply the quadratic formula: x=(-b +/- sqrt(b2-4ac))/2a where a=4, b=-3 and c=-1. Substituting the values into the formula gives: x=(-(-3) +/- sqrt((-3)2-4(-4)))/2a. Simplifying gives: x=(3 +/- sqrt(25))/8. Solving this gives x=1 and x=-0.25.
SM
Related Maths GCSE answers
All answers ▸What is 64^1/2 equal to?
At whats points does the graph of (t^2)+8t+7 intersect the x axis
A cone has radius 6cm and height 5cm. Work out its volume in terms of pi. (Formula for the volume of a cone is V=(1/3)pi(r)^2h)
Find the equation of the straight line that is tangent to the curve 2x^2 - 5x - 3 =0 when x = 3.