Point A (-3,5) and point B (1,-15) are to be connected to form a straight line, fing the equation of the line in the form y=mx+c?

First identify your x1, y1 and x2,y2. It is helpful to write this above the two points A and B. To find the gradient the following equation can be used (I will show equation on board),as u can see the X1, Y1 AND x2,y2 we highlighted earlier can be subbed in with respect the their +ive and - ive signs to get the gradient of the line (need be simplify should be -5). Then pick either point A or B. The substitute into the equation of a straight line (I will show this). From here I will simplify (again I will show this and rearrange to find the equation of the line). final answer is y= -5x+10.

CW
Answered by Charuka W. Maths tutor

5978 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Find x: 4x + 7 = 27


Using factorization, solve x^2 + 10x + 24 = 0


Solve this simultaneous equation: 3x + y = 10, x + y = 4


Solve 9x-4=7(x+2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning