4x^{2}-3x+1=2The first step is to **rearrange** the equation, equating it to zero: 4x^{2}-3x+1-2=0 which gives 4x^{2}-3x-1=0. Next we apply the quadratic formula: x=(-b +/- sqrt(b^{2}-4ac))/2a where a=4, b=-3 and c=-1. **Substituting** the values into the formula gives: x=(-(-3) +/- sqrt((-3)^{2}-4(-4)))/2a. **Simplifying** gives: x=(3 +/- sqrt(25))/8. **Solving** this gives x=1 and x=-0.25.