Work out the gradient of the tangent to the curve (y=x^2-x-2) at the point where x=2
y=x^2-x-2y=(x+1)(x-2)The gradient (dy/dx) measures the rate of the change in y with respect to x. So this can be used to help us find the gradient of a function at any point along it. The question asks the to find the gradient when x=2. So firstly we have to differentiate the curve.dy/dx=2x-1Then substitute the x value in: 2 (2) -1 = 3Therefore the gradient of the tangent is 3
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