Given that Y=(x+3)(x+5); find dy/dx

Y=(x+5)(x+3) ............(1)The above expression on the right is a product of two expressions,Hence, product rule differentiation method will be employed as stated below:Y(u,v)=U(x).V(x) .........(2)dy/dx=Udv/dx + V.du/dx ............(3)But comparing (1) and (2) above we have, U=x+3....... (4) V=x+5 ......(5)Therefore by differentiation rule:Y=xn ; dy/dx=nxn-1Applying the above rule to (4) and (5) du/dx=1 .....(6) dv/dx=1 ....(7) Substituting (4) to (7) for (3) we have,dy/dx= (x+3).1 + (x+5).1 ...(8)Simplifying (8) above,dy/dx=x+3 +x+5=2x+8=2(x+4)

DE

Related Maths A Level answers

All answers ▸

Use implicit differentiation to find the derivative of 2yx^2, with respect to x.


Given that y > 0, find ∫((3y - 4)/y(3y + 2)) dy (taken from the Edexcel C4 2016 paper)


Integrate lnx


b) The tangent to C at P meets the coordinate axes at the points Q and R. Show that the area of the triangle OQR, where O is the origin, is 9/(3-e)