Given that Y=(x+3)(x+5); find dy/dx

Y=(x+5)(x+3) ............(1)The above expression on the right is a product of two expressions,Hence, product rule differentiation method will be employed as stated below:Y(u,v)=U(x).V(x) .........(2)dy/dx=Udv/dx + V.du/dx ............(3)But comparing (1) and (2) above we have, U=x+3....... (4) V=x+5 ......(5)Therefore by differentiation rule:Y=xn ; dy/dx=nxn-1Applying the above rule to (4) and (5) du/dx=1 .....(6) dv/dx=1 ....(7) Substituting (4) to (7) for (3) we have,dy/dx= (x+3).1 + (x+5).1 ...(8)Simplifying (8) above,dy/dx=x+3 +x+5=2x+8=2(x+4)

DE
Answered by Dr Edosa O. Maths tutor

3044 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given the equation 0=5x^2+3xy-y^3 find the value of dy/dx at the point (-2,2)


∫(3x+4)2dx


Find dy/dx when y = x(4x + 1)^1/2


Express (x + 1)/((x^2)*(2x – 1)) in partial fractions


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning