Find the value of x which satisfies the following equation 3x^2 +6x+3 = 0

Factorise the equation: (3x+3)(x+1) = 0. Anything multiplied by 0 is equal to 0 therefore (x+1)=0 and (3x+3) = 0. Solve for x: if x+1 =0 you need to subtract 1 from x to work out what x is (do the opposite of the sum) therefore x = -1Now do the same to the other equation: 3x +3 = 0. Subtract 3 and then divide by 3. x = -1. Therefore the final value of x is -1.

AS
Answered by Aiysha S. Maths tutor

2892 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve: x^2 + x - 12 = 0


f is a function such that f(x)=2/(3x-3) Find the inverse function and ff^-1


How do you know which circle theorems to use when answering a question?


Work out the point at which the line y = x^2 + 4x + 4 hits the y-axis and the x value of its turning point.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences