Find an equation for the straight line connecting point A (7,4) and point B(2,0)
In this question we will use the fact we know a straight line can be written in the form (y-y1)=m(x-x1). Where m is the gradient and (x1,y1) is a point on the line. We already have a point A so can say x1=7 and y1=4 (we could have used point B instead but it won't make a difference)Now we just need to find the gradient of the line. To do this we can use the equation m=(y1-y2)/(x1-x2) . Subbing in the numbers this gives us m=(4-0)/(7-2)=4/5=0.8
Now we can combine this all to give us the equation of the line as y-4=0.8(x-7). Rearranging gives y=0.8(x-2), the form Edexcel wants.
HM
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