Given that y= 1/ (6x-3)^0.5 find the value of dy/dx at (2;1/3)

Let u=6x-3 , then y=u^-0.5hence, du/dx=6 and dy/du= -0.5u^-3/2then, as dy/dx =dy/du * du/dx dy/dx=(-0.5u^-3/2 )*6= -3(6x-3)^-3/2substitute x=2 to give the required value required value : -1/9

PN
Answered by Polina N. Maths tutor

3611 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I differentiate and integrate powers of x?


Find an equation for the straight line connecting point A (7,4) and point B(2,0)


Given a table showing grouped data and the frequency of each class, find the median Q2


Find the binomial expansion of (2+x)^3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences