Given that y= 1/ (6x-3)^0.5 find the value of dy/dx at (2;1/3)

Let u=6x-3 , then y=u^-0.5hence, du/dx=6 and dy/du= -0.5u^-3/2then, as dy/dx =dy/du * du/dx dy/dx=(-0.5u^-3/2 )*6= -3(6x-3)^-3/2substitute x=2 to give the required value required value : -1/9

PN
Answered by Polina N. Maths tutor

3684 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A and B have coordinates (2,3) and (5,15), respectively. Together they form line l. Find the equation for the line r that goes through C(7,-2) and is perpendicular to l. Give the answer in the format of y=mx+b


differentiate x^2 + y^3 + xy respect to x


You are given the function f(x)=x^3-x^2-7x+3, and that x=3 is a root of f(x)=0. Find the exact values of the other 2 roots. (6 marks)


Differentiate y=x^x with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning