Make 'a' the subject of the formula: p = (3a + 5) / (4 - a)

Firstly, multiply the whole equation by (4 - a) to cancel out the denominator, so the equation becomes: p(4 - a) = (3a + 5). Then expand the brackets: 4p - ap = 3a +5. Then rearrange the equation to: 4p - 5 = 3a + ap, so you can factorise 'a' into brackets: 4p - 5 = a(3 + p). Now make 'a' the subject by dividing (4p - 5) by (3 + p), so your equation becomes: a = (4p - 5) / (3 + p).

GR

Related Maths GCSE answers

All answers ▸

Factorise fully 27x^2 - 3


Solve the equation "3y + 5 = 11" to find the value of y.


(Q20 Non-Calculator paper, Higher Tier) Solve algebraically the simultaneous equations: x^2 + y^2 = 25 and y – 3x = 13


Why does the translation y=f(x+2) translate the graph f(x) 2 units left instead of 2 to the right?