Solve the following simultaneous equation: y= x^2 - 3x + 4 y - x = 1

When it comes to solving simultaneous equations the way you structure your working out will really help you get to the correct answer. The layout can be used for all simultaneous equations and will make even the more complicated ones seem a lot less daunting. Firstly label the two equations: y= x2 - 3x + 4  (1) and y - x = 1 (2). Substitute (1) into (2). x2 - 3x + 4 - x = 1 This equation becomes (3). Solve (3) by putting all the terms onto one side making sure x2 stays positive to simplify. x2 - 4x + 3 = 0. Now factorise the equation(x-3)(x-1) = 0. Either x - 3 = 0 or x-1=0, therefore x = 3 or x = 1. Now substitute each possible answer into the simplest simultaneous equation which would be (2) to solve for y. When x = 3 y - 3 = 1 y = 4 When x = 1 y - 1 = 1 y = 2.

Answered by Anisha P. Maths tutor

4642 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Describe and explain the change in the shape of the graph y=x^2 and y=x^2 + 2.


Solve the following simultaneous equations: x^2 + 2y = 9, y = x + 3


What is the hypotenuse of the triangle if the other 2 sides are 8cm and 6cm?


What is 90 million in standard form?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy