Solve the Simultaneous equation: 6x+3y=13, 14x-9y=9?
First we need to eliminate one of the Variables, to have an equation dependant on one variable. The coefficient for y in equation two is a third of the coefficient of the y in the second equation. Therefore, time the first equation by three to get 18x+9y=39. Now you can cancel the y out in each equation by adding the two variable together. This gets you 32x=48, from this you get that x=3/2. Now you have the value of one of the variables so you can plug in the value into one of the equations to obtain a value for the other variable. Plugging in value of x into the first question to obtain: 3y+9=13. Tidy up the equation to get 3y=4. From this you obtain that y=4/3. Hence the values for the two variables are: x=3/2, y=4/3
MM
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