Differentiate sin(x)cos(x) with respect to x?
You will have to use the Product Rule. The Product rule: when y=f(x)g(x), then dy/dx=f'(x)g(x)+f(x)g'(x). In this example, f(x)=sin(x) and g(x)=cos(x). Hence f'(x)=cos(x) and g'(x)=-sin(x). Using these and subbing into the Product rule, dy/dx=cos2(x)-sin2(x).
MM
Related Maths A Level answers
All answers ▸a) show that (cosx)^2=8(sinx)^2-6sinx can be written as (3sinx-1)^2=2 b)Solve (cosx)^2=8(sinx)^2-6sinx
Consider the function f (x) = (2/3) x^3 + bx^2 + 2x + 3, where b is some undetermined coefficient: (a) find f'(x) and f''(x) and (b) if you know that f(x) has a stationary point at x = 2, use this information to find b.
Solve the integral: int(x^3+4x^2+sinx)dx.
How do I plot a graph of y=x^3-9x?