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Solve 2^(3x-1) = 3

2^{3x - 1} = 3log₂(2^3x-1) = log₂(3)3x - 1 = log₂(3)3x = 1 + log₂(3)x = ¹/₃ + ¹/₃log₂(3)

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Answered by Jacob B. • Maths tutor

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