Find the gradient of the tangent to the curve y=4x^2 - 7x at x = 2

First, we differentiate our equation using the power rule:dy/dx = 8x - 7This is the gradient of our tangent, to the original equation, at any point x. So, to calculate the gradient at x = 2, we substitute this value into dy/dx.So, we have: gradient = 8(2) - 7 = 9 as required.

LA
Answered by Luke A. Maths tutor

4449 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate 5cos(3x - 1) with respect to x


Show that cosh(x+y) = cosh(x)cosh(y) + sinh(x)sinh(y)


Find the stationary points of y = 4(x^2 - 4)^3


Given f(x) = (x^4 - 1) / (x^4 + 1), use the quotient rule to show that f'(x) = nx^3 / (x^4 + 1)^2 where n is an integer to be determined.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences