Find the gradient of the tangent to the curve y=4x^2 - 7x at x = 2

First, we differentiate our equation using the power rule:dy/dx = 8x - 7This is the gradient of our tangent, to the original equation, at any point x. So, to calculate the gradient at x = 2, we substitute this value into dy/dx.So, we have: gradient = 8(2) - 7 = 9 as required.

LA
Answered by Luke A. Maths tutor

5153 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate the following function by parts and reduce it to it's simplest form. f(x) = ln(x).


A curve has an equation: (2x^2)*y +2x + 4y – cos(pi*y) = 17. Find dy/dx


Find the derivative of the function y=3x^2e^(2x)sin(x).


Express 2(x-1)/(x^2-2x-3) - 1/(x-3) as a fraction in its simplest form.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning