Find the gradient of the tangent to the curve y=4x^2 - 7x at x = 2
First, we differentiate our equation using the power rule:dy/dx = 8x - 7This is the gradient of our tangent, to the original equation, at any point x. So, to calculate the gradient at x = 2, we substitute this value into dy/dx.So, we have: gradient = 8(2) - 7 = 9 as required.
LA
Related Maths A Level answers
All answers ▸How can I find all the solutions to cos(3x) = sqrt(2)/2 for 0<=x<=2pi ?
Show that x^2+6x+11 can be written in as (x+p)^2+q, where p and q are integers to be found.
Curve C has equation y=(9+11x)/(3-x-2x^2). Find the area of the curve between the interval (0, 1/2). State your answer in exact terms.
We are given y=(x^2)+3x-5. Find the derivative of y in terms of x.