Differentiate dy/dx ((2x^3)+(x^2)-(4x)+7)

Differentiate each term in the equation separately then put then put the differentiated equation back together.First we start with (2x³):2 x 3 = 6 and 3-1=2 so we get the differentiated term of 6x²then we move onto the next term x² which is differentiated to 2xnext we get -4x to -4and finally when we differentiate a number on its own it goes to 0 so our final term of 7 disappears. When we put all the differentiated terms back together we get our final result of dy/dx (2x³ + x² -4x + 7) = 6x² + 2x -4