Find the derivative of sin(x)/x^3 with respect to x
First, bring the x to the numerator (top) as x^(-3). Then use the chain rule: State the first times derivative of the second plus state the second times the derivative of the first.State sin(x), then multiply by the derivative of x^(-3) which we get by bringing the power of -3 down and then subtracting one from the power. Gives us sin(x)*(-3x^(-4)).Then state x^(-3) and multiply by the derivative of sin(x), which we know is cos(x). Gives us x^(-3)*cos(x).Adding the two terms together gives us the final answer of: -3x^(-4)*sin(x)+x^(-3)*cos(x).Could move the negative powers if necessary for question.
TD
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