Solve:

x2 + y2 = 25 y – 3x = 13 Rearrange the second equation: y = 13 + 3x Substitute the rearranged question in the first equation: x2 + (13 + 3x)2 = 25 Solve: x2 + 169 + 9x2 + 78x - 25 = 0 10x2 + 78x + 144 = 0 5x2 + 39x + 72 = 0 x = (-39 +- /1521-1440)/10 x = (-39 +-9)/10 x = -4.8, x = -3 Subsitute these two values in the rearranged equation: x = -4.8 --> y = 13 + 3*(-4.8) = -1.4 x = -3 --> y = 13 + 3*(-3) = 4

BJ
Answered by Bandana J. Maths tutor

3234 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Anna and James share out £40 in the ratio 5:3 in that order. How much do they each get?


Solve ((3x+2)/(x-1)) +3 =4


Make x the subject of the formula: 3(2x-y)=ax-4


If a=2 and b=3 , find the value of 2(a−b)+3(a+b)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning