Solve:

x2 + y2 = 25 y – 3x = 13 Rearrange the second equation: y = 13 + 3x Substitute the rearranged question in the first equation: x2 + (13 + 3x)2 = 25 Solve: x2 + 169 + 9x2 + 78x - 25 = 0 10x2 + 78x + 144 = 0 5x2 + 39x + 72 = 0 x = (-39 +- /1521-1440)/10 x = (-39 +-9)/10 x = -4.8, x = -3 Subsitute these two values in the rearranged equation: x = -4.8 --> y = 13 + 3*(-4.8) = -1.4 x = -3 --> y = 13 + 3*(-3) = 4

BJ
Answered by Bandana J. Maths tutor

3092 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Given that f(x ) = 4x^3 + 12, evaluate f ( −2) .


A 20-foot ladder is leaning against a vertical wall. The bottom of the ladder is pulled away horizontally from the wall at 3 feet per second. How fast is the top of the ladder sliding down the wall when the bottom of the ladder is 10 feet away?


Find the area under the graph between x=0 and x=2 when f(x)=x^2 +2, give your answer as an exact value.


Expand these brackets 3x(x - 2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning