Find the derivative of f(x)=x^2log(2x)
Use the product rule (f'(x)=u'v+uv')
Let u=x2 => u'=2x
Let v=log(2x) => v'=2/(2x) => v'=1/x
Therefore f'(x)=2xlog(2x)+x2/x
f'(x)=2xlog(2x)+x
DB
Use the product rule (f'(x)=u'v+uv')
Let u=x2 => u'=2x
Let v=log(2x) => v'=2/(2x) => v'=1/x
Therefore f'(x)=2xlog(2x)+x2/x
f'(x)=2xlog(2x)+x
