A curve f(x,y) is defined by sin(3y)+3ye^(-2x)+2x^2 = 5. Find dy/dx

In questions where we have a function of x and y equal to a constant, we need to find dy/dx indirectly.We use the formula (df/dx) + (df/dy)(dy/dx) = 0So all we do is differentiate each term in the function with respect to x (assuming y is a constant) to give us our df/dx term, which is 0-6ye-2x+4x.Then we differentiate each term with respect to y (now assuming x is a constant) to give us our df/dy term, which is 3cos(3y)+3e2x+0.Plugging these terms directly into our formula and re-arranging for dy/dx we get:dy/dx = (6ye-2x-4x)/(3cos(3y)+3e-2x)

LW
Answered by Lewie W. Maths tutor

3992 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

find the integral of f'(x)=2x+5


How do you differentiate (2x+xe^6x)/(9x-(2x^2)-ln(x)) w.r.t. x?


Factorise 6x^2 + 7x - 3=0


Integrate y= x^3+3x^2-4x-7 between x values 1 and 3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning