Find minimum and maximum of x^2+1 if they exist

There are several methods of finding the extrema(plural of extremums or in other words minimum or maximum values) of a function.

For now we will analyse the function using the dy/dx of f(x)=y=x+1, f`(x) = 2x
The sign of the diferentiation of the function change at x=0. Therefore for x<0 dy/dx<0 and the function is declining. For x>0 dy/dx>0 and the function is uprising. We can conclude that there is a minimum at x=0. We cannot find a maximum of the function as it approaches infinity.
 

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Answered by Pavel G. Maths tutor

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solve dy/dx = y(sec x)^2


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