Find the equation of the tangent to the curve y=3x^3+x^2+5 at the point (1,9)

y=11x-2

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Answered by Ethan W. Maths tutor

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Given that the graph f(x) passes through the point (2,3) and that f'(x)=6x^2-14x+3, find f(x).


Differentiate y = x^3− 5x^2 + 3x


integrate from 0 to 2: 2x*sqrt(x+2) dx


(i) Prove sin(θ)/cos(θ) + cos(θ)/sin(θ) = 2cosec(2θ) , (ii) draw draph of y = 2cosec(2θ) for 0<θ< 360°, (iii) solve to 1 d.p. : sin(θ)/cos(θ) + cos(θ)/sin(θ) = 3.


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