Solve x/2 + 3x/(x+) = 1
(x/2) + 3x/(x+1) = 1x(x+1) + 6x = 2x + 2x2 + x + 6x - 2x = 2x2 + 5x - 2 = 0
Using the quadratic formula,
x1 = (-5+(29)1/2)/2x2 = (-5-(29)1/2)/2
ED
(x/2) + 3x/(x+1) = 1x(x+1) + 6x = 2x + 2x2 + x + 6x - 2x = 2x2 + 5x - 2 = 0
Using the quadratic formula,
x1 = (-5+(29)1/2)/2x2 = (-5-(29)1/2)/2