How do you solve simultaneous equation where one of them involves powers?

Example: y - 3x = 2 , x2 + y2 = 4 y= 3x + 2 x2 + (3x+2)2 = 4 10x2+ 12x + 4 = 4 10x2+12x=0 x(10x+12)=0 x=0 or x=-1.2 y=30 + 2 = 2 (0,2) is a solution y = 3-1.2 + 2=-1.6 (-1.2,-1.6) is a solution

LF
Answered by Luke F. Maths tutor

2921 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve: x^2 + x - 12 = 0


3 teas and 2 coffees have a total cost of £7.80. 5 teas and 4 coffees have a total cost of £14.20. Work out the cost of one tea and the cost of one coffee.


solve simultaneous equations: 2x² + 3y² = 14 , x = 2y-3


How would you solve the simultaneous equations 2x + y = 7 and 3x - y = 8


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning