The equation 5x sqaured + px + q , where p and q are constants, has roots α and α + 4. (a) Show that p squared = 20q +400.

a+a+4 = -p/5a+2 = -p/10(a+2)sqaured = q/5 +4p sqaured/100 = q/5 +4p sqaured = 100(q/5 +4)implies p squared = 20q+400

AT
Answered by Ahmed T. Maths tutor

5675 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you solve simultaneous questions?


How do you integrate tan^2(x)?


Given y= sqrt(x) + 4/sqrt(x) + 4 , find dy/dx when x=8 giving your answer in form Asqrt(2) where A is a rational number.


Let f(x) = x * sin(2x). Find the area beneath the graph of y = f(x), bounded by the x-axis, the y-axis and the line x = π/2.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences