Solve the simultaneous equations: 2x+5y=25, x=y+2

using our second equation, we can see that x=y+2. Therefore we can sub x into the first equation. This will give us 2*(y+2)+5y=25. We can go ahead and expand the brackets, which gives us 2y+4+5y=25. We can combine the y terms which gives 7y+4=25. We can take 4 away from both sides with gives 7y=21, and divide both sides by 7 so y=3. We can sub 3 into y in the original equation, to give that x=5.

LW
Answered by Louis W. Maths tutor

4189 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve: 2((x)^2) + 7x + 3, for x


Solve: x^2+x-6=0


The equation of line 1 is y=3x-2 and the equation of line 2 is 3y-9x+5=0. Show the two lines are parallel.


Solve the following simultaneous equations: (1) 4x+y=7 and (2) 3x+2y=9


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning