A ball is released from rest at a height of 4m. At what speed does it hit the ground?

First write out information from the question.s=4m u=0m/s v=? a=9.8m/s2 t=Choose correct "suvat" equation: v2=u2+2asSubstitute in known variables.Obtain v= 8.9m/s

MA
Answered by Molly A. Maths tutor

3997 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

What is the indefinite integral of cos^2x?


Find the derivative with respect to x, of 5cos(x)+ 4sin(x)


The Curve C shows parametric equations x = 4tant and y = 5((3)^1/2)(sin2t) , Point P is located at (4(3)^1/2, 15/2) Find dy/dx at P.


Solve for 0<=θ<π, the equation sin3θ-(sqrt3)cosθ=0 (C2)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning