A ball is released from rest at a height of 4m. At what speed does it hit the ground?

First write out information from the question.s=4m u=0m/s v=? a=9.8m/s2 t=Choose correct "suvat" equation: v2=u2+2asSubstitute in known variables.Obtain v= 8.9m/s

MA
Answered by Molly A. Maths tutor

4225 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the derivative for y=5x^3-2x^2+7x-15


Solve the equation: log5 (4x+3)−log5 (x−1)=2.


Using the trigonometric identity for tan(A + B), prove that tan(3x)=(3tan(x)-tan^3(x))/(1-3tan^2(x))


C1 - Simplifying a fraction that has a root on the denominator


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning