The curve C has a equation y=(2x-3)^5; point P (0.5,-32)lies on that curve. Work out the equation to the tangent to C at point P in the form of y=mx+c
Firstly you should work out the first derivative of the equation y= After differentiating the equation, sub the x value of the point P into the first derivative. This should give you the gradient of the equation. After getting the gradient of the tangent, you could use the y and x value of point P and sub it into the equation of y=mx+c to work out the y intercept (c). This would give you the answer.
MR
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