The curve C has a equation y=(2x-3)^5; point P (0.5,-32)lies on that curve. Work out the equation to the tangent to C at point P in the form of y=mx+c

Firstly you should work out the first derivative of the equation y= After differentiating the equation, sub the x value of the point P into the first derivative. This should give you the gradient of the equation. After getting the gradient of the tangent, you could use the y and x value of point P and sub it into the equation of y=mx+c to work out the y intercept (c). This would give you the answer.

MR
Answered by Mohammed R. Maths tutor

3229 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the values of x that satisfy the following inequality 3x – 7 > 3 – x


Find the gradient of the curve y=sin(x^2) + e^(x) at the point x= sqrt(pi)


Find the cross product of vectors a and b ( a x b ) where a = 3i + 6j + 4k and b = 6i - 2j + 0k.


The element of a cone has length L. For what height H (with respect to L) will the volume of the cone be the largest?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning