Differentiate y = 4ln(x)x^2
So we want to differentiate y = 4x2ln(x) with respect to y. For this we need to use the product rule.
The product rule is D {f(x)g(x)} = f(x)g'(x) + g'(x)f(x)
We can therefore make f(x) = 4x2 and g(x) = ln (x)
f'(x) = 8x nad g'(x) = 1/x
Therefore dy/dx = 8xln(x) + 4x2/x which can be simpliefied to 8xln(x) + 4x, which can be further simplified to get the answer:
4x(2ln(x) + 1)
BP
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