Differentiate y = 4ln(x)x^2

So we want to differentiate y =  4x2ln(x) with respect to y. For this we need to use the product rule.

The product rule is D {f(x)g(x)} = f(x)g'(x) + g'(x)f(x)

We can therefore make f(x) = 4xand g(x) = ln (x)

f'(x) = 8x nad g'(x) = 1/x

Therefore dy/dx = 8xln(x) + 4x2/x which can be simpliefied to 8xln(x) + 4x, which can be further simplified to get the answer:

4x(2ln(x) + 1)

BP
Answered by Beth P. Maths tutor

6385 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Solve the Equation: 2ln(x)−ln (7x)=1


Differentiate x^5 + 3x^2 - 17 with respect to x


Solve the following equation: x^(3) - 6x^(2) + 11x - 6 = 0


How do I integrate x/(x^2 + 3) ?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning