Find the x co-ordinate of stationary point of the graph y=5x^3 +3x

When you differentiate the function that gives the gradient. Therefore differentiate to get dy/dx= 15x^2 + 3. Make this equal to 0 to get 15x^2 + 3=0 and rearrange to get the value of x as required so 15x^2= -3 and so on

VJ
Answered by Vinay J. Maths tutor

3306 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate ∫x^4+5x^3+sin(2x) dx


Find the derivative of y=arcsinx


find the integral of ((3x-2)/(6x^2-8x+3)) with respect to x between x=2 and x=1. (hint use substitution u=denominator)


Differentiate y = 15x^3 + 24x^2 + 6 with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning