Solve the simultaneous equations: 1) 4x - 2y = 28, 2) 4y - 3x = -36.

Before starting, look whether either equation has common factors. Equation 1 does common factor 2, so divide it by 2 both sides to get 1) 2x - y = 14. Rearrange 1) to get one unknown in terms of the other. In this case, y as follows: 2x = 14 + y, 2x -14 = y. Substitute y in the second equation 2) using y = 2x - 14: 4(2x - 14) -3x = -36,going to 8x - 56 -3x = -36, move numbers to right and simplify x terms on the left: 8x - 3x = 56 - 36 giving 5x = 20 dividing by 5 to get x = 4. Now x = 4 is known, so substitute into the first equation 1) y = 2x - 14 to get y: y = 2(4) -14 going to y = 8 - 14, hence y = -6. Final Answer: x = 4, y = -6

AH
Answered by Aaron H. Maths tutor

4294 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is the photoelectric effect? (A-Level Physics)


If we take a number and square it, the answer is also the product of the two numbers either side of it plus one. Prove algebraically that this works for all numbers.


From June 2015 Edexcel paper: Solve 7x + 8 = 2x – 3


Solve the simultaneous equations: 3x + y = -4 and 3x - 4y = 6


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning