Rearrange the equation y = 3(x+1)/4, making x the subject.

Firstly, before we even approach the bracket containing the x term, we want to deal with the fraction. The first step should be multiplying by 4 to cancel out the denominator on the right. This leaves us with 4y = 3(x+1). In the second step, we divide by 3 which cancels out the 3 on the right hand side and therefore allow us to access the x term in the bracket. We then have 4y/3 = x+1. The last step is to subtract the 1 on the right hand side. This leaves us with 4y/3 - 1 = x.

MC
Answered by Mustafa C. Maths tutor

3576 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Prove that (4x–5)^2 – 5x(3x – 8) is positive for all values of x.


Solve x^(2) + 7x + 6 = 0.


Solve 2x^2 + 7x + 6 = 0


How do I solve a simultaneous equation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning