Solve simultaneously, 2x-3y=16 and x+2y=-6

In order to solve this we need to make two of the terms the same and use an elimination method so we are left with only one unknown rather than two. We will multiply x + 2y = -6 by 2 in order to get 2x + 4y = -12. Now we have 2x in both our equations. Since the signs of the 2x are the same (both are positive) we will subtract the equations from each other, therefore getting rid of the 2x term. By subtracting the equations from each other we are left with one equation, 28 = -7y. From this we can work out that y = -4. By substituting this value of y=-4 back into one of the original equations in the question we get x=2.

GG
Answered by Gemma G. Maths tutor

6047 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations: x + 2y = 13, 4x - 3y = 8.


How do I use Pythagoras' Theorem to calculate the hypotenuse of a triangle?


There are 30 yellow sweets and 10 black sweets in a bag. Two sweets are taken out at random without replacement. Work out the probability that the two sweets are the same colour.


Solve the simultaneous equation: 2x + y = 18, x - y = 6


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning