How do you solve the simultaneous equations x^2+y=1 and -x+y=-1

First rearrange the second equation so that it's equal to y. You do this by adding x and y to both sides of the equation. You should then have y=x-1. Next you should sub y=x-1 into the first equation, x2+y=1. You should now be left with x2+x-1=1. This can be rearranged by subtracting 1 from each side to create the quadratic equation x2+x-2=0. This can be solved in which ever way you prefer; I would factorise it, leaving you with (x+2)(x-1)=0. Therefore x=-2 or x=1

CM
Answered by Chloe M. Maths tutor

3292 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A rectangle has sides of length 4x cm and (x+3)cm and has an area less than 112 cm^2, find the set of values x can take


The nth term of a sequence is 7n-4. Write down the 4th term and the 10th term of the sequence. The first four terms of a different sequence are 9, 13, 17, 21. Find an expression for the nth term of this sequence.


£X was invested for 5 years, earning compound interest of 2% per year. After 5 years the total value of the investment was £11,040.81. How do I calculate the value of the invested amount £X?


How do you solve the equation '2x + 1 = 5'?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning