Solve simultaneously 2x-y=2, 3x+2y=17 to calculate values of x and y.

This problem can be solved through substitution. The first equation provided in the question should be rearranged to give y=2x-2. This equation for y can be directly substituted into the second equation. This would give, 3x+2(2x-2)=17 therefore eliminating the y term. By expanding this equation, we get 3x+4x-4=17 which simplifies further down to 7x=21. This gives a value of x=3. In order to calculate y, we can sub this value of x into any of the equations provided in the question. For example, substituting into the first equation gives 6-y=2. As a result, rearranging this gives a value of y=4.

WR

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations 3x+y=16, x+y=10


The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.


Calculate y=4x-6 when x=3


Factorise x 2 − x − 12