Solve the following simultaneous equations: 4x + 5y = -8 and 6x-2y = 26

1) Multiply both equations so we have the same coefficient of one of the variables. This allows us to eliminate one of the variables and solve for the other. (4x + 5y = -8) --> Multiply by 3 so we have (12x + 15y = -24) and (6x - 2y = 26) --> Multiply by 2 so we have (12x - 4y = 52). 2) Subtract the second equation for the first leading to (0x + 19y = -76). Divide both sides by 19 leading to (y = -4) 3) Substitute back into one of the original equations leading to 4x + 5(-4) = -84x -20 = -8 , 4x = 12, and finally x = 3. Hence we have the solution x = 3 and y = -4

MH
Answered by Maria H. Maths tutor

4066 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

A right-angle triangle has three sides (diagram would be included). Side A = 3cm; Side B = 7cm. What is the length of Side C (the hypotenuse)? Give your answer to 2 d.p.


Factorise x^2 + 5x + 6


What are the differences between arithmetic and geometric sequences?


Factorise and solve the quadratic : 3x^2 + 15x +18 = 0


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences